18a^2-242=0

Solution for 18a^2-242=0 equation:

18a^2-242=0

a = 18; b = 0; c = -242;
Δ = b2-4ac
Δ = 02-4·18·(-242)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-132}{2*18}=\frac{-132}{36}
=-3+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+132}{2*18}=\frac{132}{36}
=3+2/3
$